How Do I Make A Percent For A Number That Is Not 100 (2024)

The complement of the event is diamond, club or spade.

The complement of an event means " to not choose the mentioned one" .

That is in mathematics we define complement as 1 - E, which is also written as E with a bar, here E represents the event.

In this question we would have to pick a card which is complementary to the heart that is the card needs to be a diamond, spade or a club.

Thus the complement of the event is diamond, club or spade.

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The Divisor is 1.5 , the Dividend is 4.5 and the quotient is 3.

As per the question we need to create a division problem where both the divisor and the dividend are decimals and the quotient must be a whole number greater than 1.

So, Let us suppose divisor as 1.5 . Now the dividend must be a decimal number which is greater than 1.5, let's say 5.5.

Now on dividing 5.5 by 1.5,

Divisor = 1.5

Dividend = 4.5

(Dividend/Divisor) = ( 4.5 / 1.5 ) = 3

Quotient = 3

On dividing dividend by divisor the quotient is 3 which is a whole number greater than 1.

So, we can conclude that the Divisor is 1.5 , the Dividend is 4.5 and the quotient is 3.

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The products of the fractions given are:

1. (-3/4)(7/8) → -21/32

2. (2/3)(-4)(9) → -24

3. (5/16)(-2)(-4)(-4/5) → -2

4. (2 3/5)(7/9) → 91/45

How to Multiply Fractions?

To multiply two or more fractions, multiply the denominators of both fractions together, and their numerators together.

1. (-3/4)(7/8)

Multiply the denominators of the fractions together, and also multiply their numerators:

= (-3 × 7) / (4 × 8)

= (-21) / (32)

(-3/4)(7/8) → -21/32

2. (2/3)(-4)(9)

Multiply the denominators of the fractions together, and also multiply their numerators:

= (2 × -4 × 9) / (3)

= -72/3 = -24

(2/3)(-4)(9) → -24

3. (5/16)(-2)(-4)(-4/5)

= (5 × -2 × -4 × -4) / (16 × 5)

= -160/80 = -2

(5/16)(-2)(-4)(-4/5) → -2

4. (2 3/5)(7/9)

= (13/5)(7/9)

= (13 × 7)/(5 × 9) = 91/45

(2 3/5)(7/9) → 91/45

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Answer:

answer is c

Step-by-step explanation:

5x+2=10

Answer: the answer is 10.875

Hope this helped :D

Answer:

10 7/8 Here you go :) ten seven eights

Step-by-step explanation:

Answer:

x = 5

Step-by-step explanation:

8x + 7 = 2x + 37 Subtract 2x from both sides of the equation

6x + 7 = 37 Subtract 7 from both sides

6x = 30 Divide both sides by 6

x = 5

Or you could plug in 5 for x and solve. If the equation is true, that is the answer

x= 5

8x + 7 = 2x + 37

8(5) + 7 = 2(5) + 37

40 + 7 = 10 + 37

47 = 47

If you try this with any other number, it will not equal. Lets try x = 11

8x + 7 = 2x + 37

8(11) + 7 = 2(11) + 37

88 + 7 = 22 + 37

95 ≠ 59 so x does not equal 11

A nearby hamburger joint sold 416 hamburgers and cheeseburgers in total on Monday. 104 hamburgers were sold.

Given that,

A nearby hamburger joint sold 416 hamburgers and cheeseburgers in total on Monday. Three times as many cheeseburgers were sold as regular hamburgers.

We have to find on Monday, how many hamburgers were sold.

Let us take hamburgers were sold as h and cheeseburgers were sold as c.

Quantity equation is h+c=416

c=3h

Substitute c =3h in h+c=416

h+3h=416

4h=416

h=104

Now,

Substitute h=104 in c=3h

c=3×104

c=312

Therefore, 104 hamburgers were sold.

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Answer: 9,875

Step-by-step explanation: 125 x 79 = 9,875

Answer:

$3.25

Step-by-step explanation:

This question tests on the concept of conversion.

Given from the question,

8.5 pounds = $27.63

(8.5 ÷ 8.5) pounds = $27.63 ÷ 8.5

1 pound = $3.25 (Rounded off to 2 decimal places)

The lowest score that Keiko is trying to score to get in the "ryo" range is , the inequality to represent this story is (x+85+57+78)/4 > 70 .

In the question ,

it is given that

Keiko need to score average above 70 to get in the ryo range

let x be the marks that Keiko scores in the next test ,

so, the average = (x+85+57+78)/4

According to the question

Average > 70

Substituting the value of average , the inequality becomes

(x+85+57+78)/4 > 70

x+85+57+78 > 280

x+220 > 280

x > 280-220

x > 60

the lowest score that Keiko should get is greater than 60 .

When the inequality x > 60 , will be graphed then the limit will be an open circle as equal to sign is not included in the inequality .

as when the numbers increases , it move towards right side

So, When the inequality is graphed, the line will have an arrow pointing towards the right .

Therefore , the lowest score that Keiko is trying to score to get in the "ryo" range is , the inequality to represent this story is greater than 60 ,

the inequality to represent this story is (x+85+57+78)/4 > 70 ,

the limit of graph will be open circle and arrow will be pointing towards right .

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The speed of the cyclist and the walker is 25 miles per hour and 16.67 miles per hour, respectively.

Speed describes how fast an object moves. It can be measured as distance over time.

speed = distance / time

Let x be the speed of the walker and 1.5x is the speed of the cyclist.

If they start "moving simultaneously in the same direction" from the same point and, after 1.5 hours, the distance between them is 12.5 miles, then

distance traveled by cyclist = distance traveled by the walker + 12.5 miles

cyclist's speed(time) = walker's speed(time) + 12.5

1.5x(1.5 hours) = x(1.5 hours) + 12.5

2.25x - 1.5x = 12.5

x = 50/3

walker's speed = 50/3 or 16.67miles per hour

cyclist's speed = 1.5(50/3)

cyclist's speed = 25 miles per hour

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Correct option is B)

Put x=3y=4

(3x+4y):(5x+6y)=(3×3+4×4):(5×3+6×4)

=(9+16):(15+24)

=25:39

(t₁......t₆) = (5, 1, 44, 10, 90, 20) is the solution of the given matrix.

(A) An augmented matrix for a system of equations is a matrix of numbers where each column represents all the coefficients for a single variable and each row represents the constants from one equation (both the coefficients and the constant on the other side of the equal sign).

The system's augmented matrix is shown here:

[tex]\left[\begin{array}{cccccc|c}1 & 1 & 1 & -\frac{1}{2} & -\frac{1}{2} & 0 & 0 \\0 & 1 & 1 & 1 & -\frac{1}{2} & -\frac{1}{2} & 0 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 0 & 1 & 0 & 0 & 10\end{array}\right][/tex]

(B) Use these row operations to convert this augmented matrix to a reduced echelon form.

Row 2 should be subtracted from row 1, row 2 from row 3, and row 3 should be added to row 2.Increase row 3 by 1.Subtract row 4 from row 3 and multiply row 4 by row 1.

Here is the augmented matrix's reduced echelon form:

[tex]\left[\begin{array}{ccccccc}1 & 0 & 0 & 0 & 0 & \frac{1}{2} & 15 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 1 & 0 & -\frac{1}{2} & -\frac{1}{2} & -11 \\0 & 0 & 0 & 1 & 0 & 0 & 10\end{array}\right][/tex]

(C) There are more rows:

[tex]\begin{array}{lllllll}0 & 0 & 0 & 0 & 0 & 1 & 20\end{array},\\\begin{array}{lllllll}1 & 1 & 1 & 0 & 0 & 0 & 50\end{array}[/tex]

Augmented matrix:

[tex]\left[\begin{array}{ccccccc}1 & 0 & 0 & 0 & 0 & \frac{1}{2} & 15 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 1 & 0 & -\frac{1}{2} & -\frac{1}{2} & -11 \\0 & 0 & 0 & 1 & 0 & 0 & 10 \\0 & 0 & 0 & 0 & 0 & 1 & 20 \\1 & 1 & 1 & 0 & 0 & 0 & 50\end{array}\right][/tex]

(D) You must employ these row operations in order to solve the system.

Subtract row 1 from row 6, row 2 from row 6, row 3 from row 6, swap rows 5 and 6, add row 5 to row 3, multiply row 5 by 2, subtract row 1 from row 6, and row 1 from row 6 multiplied by 1/2. Add row 6 multiplied by 1/2 to row 3.

[tex]\left[\begin{array}{lllllll}1 & 0 & 0 & 0 & 0 & 0 & 5 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 1 & 0 & 0 & 0 & 44 \\0 & 0 & 0 & 1 & 0 & 0 & 10 \\0 & 0 & 0 & 0 & 1 & 0 & 90 \\0 & 0 & 0 & 0 & 0 & 1 & 20\end{array}\right][/tex]

Therefore, (t₁......t₆) = (5, 1, 44, 10, 90, 20) is the solution of the given matrix.

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A school's fifth graders prepare a paper about a historical figure for a contest. The total number of students who participated in the contest is 153.

Given that,

A school's fifth graders prepare a paper about a historical figure for a contest.

The contest is being competed in by $5 classes of $25 students and $1 classes of $28 students.

We have to calculate the number of students who enter the contest.

We get

=5×25+1×28

Multiply the terms

=125+28

Adding the terms

=153

Therefore, the total number of students who participated in the contest is 153.

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Using the definition of a midpoint and collinear points, the proof that shows that B is the midpoint of AC is explained below.

What are Collinear Points?

If three points are on a straight line, they are defined as being collinear points. That is, three points, A, B, and C are collinear points if they are on a straight line, and B is in the middle of points A and b.

What is the Midpoint of a Segment?

When a segment is divided into two equal halves, the point that lies in the middle of the segment where the segment is cut into halves is called the midpoint of the line segment.

The proof that shows that B is the midpoint of line segment AC is shown below:

Statements Reasons

a. A, B, and C are collinear a. Given

AB = BD, BD = BC

b. AB = BC b. Substitution

c. AB ≅ BC c. Definition of congruency

d. B is the midpoint d. AB ≅ BC

Thus, the proof above explains how point B is the midpoint of line segment AC in the image given.

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Answer:

-1

Step-by-step explanation:

First combine like terms on the right side (5x-10x) to get -5x +4

6-3x=-5x+4

then move the -5x over to get 2x because you would add the -5x to the -3x.

6+2x= 4

then subtract 6 on both sides.

2x=-2

to make your final answer -1.

Answer:

x = -3

Step-by-step explanation:

6x + 4 = 4x - 2

-4x -4x

--------------------

2x + 4 = -2

-4 -4

--------------------

2x = -6

÷2 ÷2

-------------

x = -3

I hope this helps!

6x + 4 = 4x -2

2x = -6

x = -3

If Lisa and Joey put the same amount of money every month in the savings account for David's future and the situation is plotted in a graph where time is on the x-axis, then there will be straight line with a constant slope.

As per the question statement, Lisa and Joey just became parents to their son, David and they decided to start a savings account for their newborn's future, where they agreed to put an equal amount of money every month.

We are required to determine the condition of the variables if the above-mentioned situation is plotted into graph and the account gets constantly filled with money as David grows older.

To solve this question, first let us consider the time to be plotted on the X-axis (As mentioned in question statement that "Time" is almost always on the x-axis) and the money collected to be plotted on the Y-axis.

Since, an equal amount of money is put into the account every month, therefore, taking 1 month as unit time to plot our graph, the money will grow diagonally in a straight line with a constant slope. Hence, both the variables (abscissa and ordinates) will increase on a constant ratio along the first quadrant.

Slope of a Line: In mathematics, the slope or gradient of a line is a value that describes both the direction and the steepness of the line and is calculated by the change in y coordinate with respect to the change in x coordinate.

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The variance of each random variable is given as follows:

a) Var(2x - y) = 10.4165.

b) Var(x + 3y - 5) = 20.833.

What is the variance of random variable?

The number that occurs when each dice is thrown is represented by an uniform variable, with bounds a = 1 and b = 6, hence the variance of each variable is calculated as follows:

Var(x) = Var(y) = (6 - 1)²/12 = 2.0833.

When two variables are added, the variance is calculated as follows:

Var(aX + bY) = a²Var(X) + b²Var(Y)

Hence, for item a, the variance is calculated as follows:

Var(2x - y) = 2²Var(x) + (-1)²Var(y) = 4Var(x) + Var(y)

The variances were calculated before, which are both of 2.0833, hence:

4Var(x) + Var(y) = 4 x 2.0833 + 2.0833 = 10.4165.

For item b, the variance is calculated as follows:

Var(x + 3y - 5) = Var(x) + 3²Var(y) + (-1)²Var(-5).

The variance of a constant is of zero, hence Var(-5) = 0, and then:

Var(x + 3y - 5) = Var(x) + 3²Var(y) + (-1)²Var(-5) = 2.0833 + 9(2.0833) = 20.833.

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Answer:

£ 10.50

Step-by-step explanation:

Mean:

a) Stacy is wrong because she found the mean of the £9.50 and £13.50. She has to find the mean of wage of 42 packers and wage of 14 truck drivers.

[tex]\sf b) Overall \ mean \ wage = \dfrac{sum \ of \ wages \ of \ 42 \ packers+ Sum \ of \ wages \ of \ 14 \ truckers}{number \ of \ packers + numbers \ of \ truck \ drivers}[/tex]

Sum of wages of 42 packers = 42 * 9.50

= £ 399

Sum of wages of 14 truck drivers = 14 * 13.50

= £ 189

[tex]\sf Overall \ mean \ wage = \dfrac{399+189}{42+14}\\\\[/tex]

[tex]\sf = \dfrac{588}{56}\\\\[/tex]

= £ 10.50

Using the number line we get the value as 5 .

In basic mathematics, real numbers are shown as a graphic of a graduated straight line called a number line.

Every point on a number line is considered to correspond to a real number, and every real number is assumed to correspond to a point.The integers are typically shown as lines of specially chosen, evenly spaced dots. Even though the picture only shows the integers, as well as numbers that are in between the integers, the line contains all real numbers, going forever in both directions. When teaching fundamental addition and subtraction with negative numbers, it is widely used as a teaching technique.

Now as represented in the number line we subtract the numbers to get

−1−(−6) = 5

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The Domain of this relation is {0,2,3,4} and the range of the relation is {-2,1,2,5}.

In the question

let us first write down the coordinates in the order from bottom to top .

The coordinates of the points are (4,-2) ,(2,1) ,(0,2) ,(0,5) ,(3,5) .

the x coordinates in the point (x,y) is called as Domain .

the y coordinates in the point (x,y) is called as Range .

Hence , the Domain of the given relation is {4,2,0,3}

writing in the order we get , Domain = {0,2,3,4}

and the range of the given relation is {-2,1,2,5}

writing in the order we get , Range = {-2,1,2,5}

Therefore , the Domain of this relation is {0,2,3,4} and the range of the relation is {-2,1,2,5} .

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Answer: 2(2−x)(x−6)

Step-by-step explanation:

The fractions are divided to give 77/144. Option A

What is a fraction?

A fraction can simply be defined as the part of a whole set or element.

The types of fractions includes;

Improper fractionsProper fractionsMixed fractionsComplex fractionsSimple fractions

Examples of simple fractions are: 1/2 , 1/4

Examples of proper fractions are; 2/3, 5/6

Examples of improper fractions are; 5/3, 9/7

Examples of mixed fractions are; 2 1/2, 3 1/4

Given the expression as;

2 3/4 ÷ 5 1/7

Turn into improper fractions

11/4 ÷ 36/7

Take the inverse of the divisor

11/4 × 7/36

Multiply the numerators and denominators

77/144

Thus, the value is 77/144

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Answer: #1 / A

Step-by-step explanation:

The expression is 0.5=[tex]\frac{a\times3+b\times4.5+c\times1}{81}[/tex]. The evaluated expression is 3a+4.5b+c=40.5

Given that,

The expression is 0.5=[tex]\frac{a\times3+b\times4.5+c\times1}{81}[/tex]

We have to evaluate the expression

Evaluating an algebraic expression involves determining its value when a particular integer is substituted for a variable. We use the given number to replace the expression's variable before applying the order of operations to simplify the expression.

Take,

0.5=[tex]\frac{a\times3+b\times4.5+c\times1}{81}[/tex]

0.5×81=a×3+b×4.5+c

40.5=3a+4.5b+c

The expression can be written in 4 ways

1st- 3a+4.5b+c=40.5

2nd- a=[tex]\frac{40.4-4.5b-c}{3}[/tex]=13.4-1.5b-c (this is the expression with subject a)

3rd- b= [tex]\frac{40.5-3a-c}{4.5}[/tex]=9-1.6a-c (this is the expression with subject b)

4th- c= 40.5-3a-4.5b (this is the expression with subject c)

Therefore, The evaluated expression is 3a+4.5b+c=40.5

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The Probability that 2 or fewer will withdraw without completing the introductory statistics course is 0.4547 .

The Binomial Distribution formula is

P(X=x) = C(n,x)*pˣ*qⁿ⁻ˣ

where ,

n is the number of trials

x is the number of times success occurs

p is the probability of success

q is the probability of failure .

In the given question ;

it is given that

students that are registered for the course = 20

so , n=20

Let x denote the number of students that withdraw without completing the course .

given that 14 % students withdraw without completing the course ,

hence p = 14% = 0.14

So , q= 1-p = 1-0.14 = 0.86

the probability that 2 or fewer will withdraw from the course is denoted by P(X ≤ 2) and is calculated using

the formula , P(X≤2)=P(X=0)+P(X=1)+P(X=2) ...(i)

using Binomial Probability we get

P(X=x) = C(n,x)*pˣ*qⁿ⁻ˣ

P(X=0) = C(20,0)*(0.14)⁰*(0.86)²⁰⁻⁰

= C(20,0)*(0.14)⁰*(0.86)²⁰

= 1*1*(0.0489)

= 0.0489

So , P(X=0)=0.0489 ...(ii)

P(X=1) = C(20,1)*(0.14)¹*(0.86)¹⁹

= 20*0.14*0.0569

= 0.1593

So , P(X=1)=0.1593 ...(iii)

P(X=2) = C(20,2)*(0.14)²*(0.86)¹⁸

= 190*0.0196*0.0662

= 0.2465

So , P(X=2)=0.2465 ...(iv)

Substituting the values of (ii) , (iii) and (iv) in (i) , we get

P(X≤2)=P(X=0)+P(X=1)+P(X=2)

P(X ≤ 2) = 0.0489 + 0.1593 + 0.2465

= 0.4547

Therefore , the Probability that 2 or fewer will withdraw without completing the introductory statistics course is 0.4547 .

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Answer:

-3

Step-by-step explanation:

your x-axis has to be 0 then the point on the y-axis is the y-intercept

These two functions' graphs do indeed intersect:

Formula 1: F(X)=2X+5

The formula 2=H(X)=3X+2

INTERSECT=(3,11)

Describe function:

a mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable).Everywhere in mathematics are functions, which are essential for building physical connections in the sciences.

According to the given data:

The first step is to generate two linear functions. I created the linear functions f(x)=2x+5 and h(x)=3x+2 (without a quadratic term). Then

You substitute a number for the x:

F(X)=2X+5 in Table 1 (H(X)=3X+2) Table 2

X=1——->Y=2+5=7 X=1------> Y=3·1+2=5

X=2---->

Y=2·2+5=9 X=2-----> Y=3·2+2=8

X=3---->

Y=3·3+5=11 X=3-----> Y=3·3+2=11

The two - dimensional functions will intersect at the X=3/Y=11 location, as demonstrated by both data tables, which is the answer.

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Answer:3

Step-by-step explanation:

If the ratio is 1:5 that means that the number of pints of apple juice is multiplied by 5 to get the nimber of pints of mango juice

Answer:

10

Step-by-step explanation:

lol XD are you trolling?